Cerium(IV) ion is a strong oxidizing agent that accepts one electron to produce cerium(III) ion: A solution

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Cerium(IV) ion is a strong oxidizing agent that accepts one electron to produce cerium(III) ion:

4+ Ce (aq) +e 3+ Ce + (aq)

A solution containing an unknown concentration of Sn2+ ions was titrated with a solution containing Ce4+ ions, which oxidize the Sn2+ ions to Sn4+ ions. In one titration 1.00 L of the unknown solution required 46.45 mL of a 0.1050 M Ce4+ solution to reach the stoichiometric point. Calculate the concentration of Sn2+ ions in the unknown solution.

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Related Book For  answer-question

Chemical Principles

ISBN: 9780618946907

6th Edition

Authors: Steven S Zumdahl

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