Compare Figs. 14.38 and 14.40. Why are they different? Because B2 is known to be paramagnetic, the
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Compare Figs. 14.38 and 14.40. Why are they different? Because B2 is known to be paramagnetic, the p2p and s2p MOs must be switched from our first prediction. What is the rationale for this? Why might one expect the s2p to be lower in energy than the p2p? Why can’t we use diatomic oxygen to help us decide whether the s2p or is lower in energy?
Fig. 14.38
Fig. 14.40
Transcribed Image Text:
E B atom 2p+ 2s B₂ molecule TV2P TUZP # # # #1 TV2P TU2p 1 I 1 020 B atom 025 -2p #2s
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Fig 1438 and 1440 differ because B2 is a paramagnetic molecule This means that the spin of the electrons is not paired up and the p2p and s2p MOs must ...View the full answer
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