Question: Ethane, C 2 H 6 , forms CH 3 radicals at 700. C in a first-order reaction, for which k r = 1.98 h 1
Ethane, C2H6, forms ·CH3 radicals at 700. °C in a first-order reaction, for which kr = 1.98 h–1.
(a) What is the half-life for the reaction?
(b) Calculate the time needed for the amount of ethane to fall from 2.26 * 10–3 mol to 1.45 * 10–4 mol in a reaction vessel of volume 500. mL at 700. °C.
(c) How much of a sample of ethane with mass of 5.44 mg placed in a reaction vessel of 500. mL volume at 700. °C will remain after 42 min?
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a To find the halflife of the reaction we can use the formula t12 ln2 k where t12 is the halflife an... View full answer
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