When 510. mg of NO 2 is confined to a reaction vessel of volume 180. mL and

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When 510. mg of NO₂ is confined to a reaction vessel of volume 180. mL and heated to 300°C, it decomposes by a second-order process. In the rate law for the decomposition of NO₂, k_r = 0.54 L · mol^–1 · s^–1.

(a) What is the initial reaction rate?

(b) How does the reaction rate change (and by what factor)
if the mass of NO₂ present in the container is increased to 820. mg?

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Chemical Principles The Quest For Insight

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Question Posted: Dec 31, 2023 01:17 AM

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When 510. mg of NO 2 is confined to a reaction vessel of volume 180. mL and

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To solve this problem we can use the secondorder rate law equation Rate kr NO22 Where kr is the rate ...View the full answer

Chemical Principles The Quest For Insight

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