Potassium iodide reacts with lead(II) nitrate in the following precipitation reaction: What minimum volume of 0.200 M

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Potassium iodide reacts with lead(II) nitrate in the following precipitation reaction:2 Kl(aq) + Pb(NO3)2(aq) 2 KNO3(aq) + Pbl2(s)

What minimum volume of 0.200 M potassium iodide solution is required to completely precipitate all of the lead in 155.0 mL of a 0.112 M lead(II) nitrate solution?

a) 348 mL 

b) 86.8 mL 

c) 174 mL 

d) 43.4 mL

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