The vanadium in a sample of ore is converted to VO 2 The VO 2 ion is subsequently titrated with MnO 4 in acidic solution to form V(OH) 4 and manganese(II) ion The unbalanced titration reaction is To titrate the solution, 26 45 mL of 0 02250 M MnO 4 was required If the mass percent of vanadium in th...

To balance the titration reaction we can use the oxidation state method MnO4 aq VO2 aq H2Ol VOH4 aq ...

The vanadium in a sample of ore is converted to VO 2+ . The VO 2+ ion

Question:

The vanadium in a sample of ore is converted to VO²⁺. The VO²⁺ ion is subsequently titrated with MnO₄^- in acidic solution to form V(OH)₄⁺ and manganese(II) ion. The unbalanced titration reaction is

MnO4 (aq) + VO+ (aq) + HO(1) - V(OH)4+ (aq) + Mn+ (aq) + H+ (aq)

To titrate the solution, 26.45 mL of 0.02250 M MnO₄^- was required. If the mass percent of vanadium in the ore was 58.1%, what was the mass of the ore sample?

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