A titration of 25.0 mL of a solution of the weak base aniline, C 6 H 5

Question:

A titration of 25.0 mL of a solution of the weak base aniline, C₆H₅NH₂, requires 25.67 mL of 0.175 M HCl to reach the equivalence point.

(a) What was the concentration of aniline in the original solution?
(b) What are the concentrations of H₃O⁺, OH⁻, and C₆H₅NH₃⁺ at the equivalence point?
(c) What is the pH of the solution at the equivalence point?

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Chemistry And Chemical Reactivity

ISBN: 9780357001172

10th Edition

Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

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Question Posted: Oct 29, 2023 05:21 AM

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A titration of 25.0 mL of a solution of the weak base aniline, C 6 H 5

Question:

C6H5NH₂(aq) + H3O+ (aq) = C6H5NH3 + (aq) + H₂O(l)

Step by Step Answer:

To solve this problem you can use the concept of stoichiometry and acidbase titration Here are the steps to answer each part of the question a Use the ...View the full answer

Chemistry And Chemical Reactivity

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