Copper(I) ion disproportionates to copper metal and copper(II) ion. (See Study Question 99.) (a) What two half-reactions
Question:
Copper(I) ion disproportionates to copper metal and copper(II) ion. (See Study Question 99.)
(a) What two half-reactions make up the disproportionation reaction?
(b) Use values of the standard reduction potentials for the two half-reactions in part (a) to determine whether this disproportionation reaction is product-favored at equilibrium.
(c) What is the equilibrium constant for this reaction? If you have a solution that initially contains 0.10 mol of Cu+ in 1.0 L of water, what are the concentrations of Cu+ and Cu2+ at equilibrium?
Data given in Question 99
Iron(II) ion undergoes a disproportionation reaction to give Fe(s) and the iron(III) ion. That is, iron(II) ion is both oxidized and reduced within the same reaction.
Step by Step Answer:
Chemistry And Chemical Reactivity
ISBN: 9780357001172
10th Edition
Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel