The dissociation of calcium carbonate has an equilibrium constant of K p = 1.16 at 800C. (a)
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The dissociation of calcium carbonate has an equilibrium constant of Kp = 1.16 at 800°C.
(a) What is Kc for the reaction?
(b) If you place 22.5 g of CaCO3 in a 9.56-L container at 800°C, what is the pressure of CO2 in the container?
(c) What percentage of the original 22.5-g sample of CaCO3 remains undecomposed at equilibrium?
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Related Book For
Chemistry And Chemical Reactivity
ISBN: 9780357001172
10th Edition
Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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