Xenon trioxide, XeO₃, reacts with aqueous base to form the xenate anion, HXeO₄⁻. This ion reacts further with OH⁻ to form the perxenate anion, XeO₆⁴⁻, in the following reaction:

Identify the elements that are oxidized and reduced in this reaction. You will note that the equation is balanced with respect to the number of atoms on either side. Verify that the redox part of this equation is also balanced, that is, that the extents of oxidation and reduction are also equal.

Transcribed Image Text:

2 HXeO4 (aq) + 2 OH-(aq) → XeO.*-(aq) + Xe(g) + Oz(g) + 2 H,O(l)