You are given a solid mixture of NaNO₂ and NaCl and are asked to analyze it for the amount of NaNO₂ present. To do so, you allow the mixture to react with sulfamic acid, HSO₃NH₂, in water according to the equation

What is the weight percentage of NaNO2 in 1.232 g of the solid mixture if reaction with sulfamic acid produces 295 mL of dry N₂ gas with a pressure of 713 mm Hg at 21.0°C?

Transcribed Image Text:

NaNO₂(aq) + HSO3NH₂(aq) → NaHSO4(aq) + H₂O(l) + N₂(g)