Naturally found uranium consists of 99.274% 238 U, 0.720% 235 U, and 0.006% 233 U. As we

Question:

Naturally found uranium consists of 99.274% 238U, 0.720% 235U, and 0.006% 233U. As we have seen, 235U is the isotope that can undergo a nuclear chain reaction. Most of the 235U used in the first atomic bomb was obtained by gaseous diffusion of uranium hexafluoride, UF6(g).

(a) What is the mass of UF6 in a 30.0-L vessel of UF6 at a pressure of 695 torr at 350 K?

(b) What is the mass of 235U in the sample described in part (a)?

(c) Now suppose that the UF6 is diffused through a porous barrier and that the change in the ratio of 238U and 235U in the diffused gas can be described by Equation 10.23. What is the mass of 235U in a sample of the diffused gas analogous to that in part (a)?

3RT/M1 3RT/M2 4rmsl V M. Urms2 ||


(d) After one more cycle of gaseous diffusion, what is the percentage of 235UF6 in the sample?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Chemistry The Central Science

ISBN: 9780321910417

13th Edition

Authors: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Question Posted: