Solve each equation in Exercises 4160 by making an appropriate substitution. 1 2 2x37x3 15 = 0
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Solve each equation in Exercises 41–60 by making an appropriate substitution.
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1 2 2x37x3 15 = 0
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2x23 7x315 0 let t x3 21 7t...View the full answer
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