If a projectile is launched vertically upward from the ground with an initial velocity of 45 ft

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If a projectile is launched vertically upward from the ground with an initial velocity of 45 ft per sec, neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by

s = -16t2 + 45t.

Which equation should be used to determine the height of the projectile after 2 sec?

A. s = 2(-16t2 + 45t) 

B. s = -16(2)2 + 45(2)

C. 2 = -16t2 + 45t 

D. 2 = -16t2

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Related Book For  answer-question

College Algebra

ISBN: 978-0134697024

12th edition

Authors: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

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