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If a projectile is launched vertically upward from the ground with an initial velocity of $95$ ft per sec$,$ then neglecting air resistance, its height $s($in feet$)$ above the ground $t$ seconds after projection is given by $s=-16t^{2}95t.$ Which equation should be used to determine the height of the projectile after $5$ sec $?$

Choose the correct answer below.

A$.5=-16t^2$

B$.s=-16(5{)}^{2}95$

C$.s=-16(5{)}^{2}95(5)$

D$.5=-16t^{2}95t$

Time Rem$$ining: $00$:$31$:$19$

$N{e}^{ln}{r}^2$