Solve the problem. The series where n! = 1 2 3 4 .... n,

Question:

Solve the problem.

The series a? a3 ea - 1 + a + 2! 3! n!

where n! = 1 · 2 · 3 · 4 ·....· n, can be used to approximate the value of e a for any real number a. Use the first eight terms of this series to approximate each expression. Compare this approximation with the value obtained on a calculator.

(a) e

(b) e^-1

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Related Book For answer-question

College Algebra

ISBN: 978-0134697024

12th edition

Authors: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

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Question Posted: Apr 10, 2019 03:05 PM

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Solve the problem. The series where n! = 1 2 3 4 .... n,

Question:

a? a3 ea - 1 + a + 2! 3! n!

Step by Step Answer:

a e 1a n 123 a Calculate a 2 3 0 1 e11 1112133 144155 1 661171 n b ...View the full answer

College Algebra

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