Question: Solve the problem. The series where n! = 1 2 3 4 .... n, can be used to approximate the value of

Solve the problem.

The seriesa? a3 ea - 1 + a + 2! 3! n!


where n! = 1 · 2 · 3 · 4 ·....· n, can be used to approximate the value of e a for any real number a. Use the first eight terms of this series to approximate each expression. Compare this approximation with the value obtained on a calculator.

(a) e 

(b) e-1

a? a3 ea - 1 + a + 2! 3! n!

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a e 1a n 123 a Calculate a 2 3 0 1 e11 1112133 144155 1 661171 n b ... View full answer

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