Question: A gymnast on the uneven parallel bars is at rest, tipped at a 45 angle from the vertical. The distance from her hands to her
A gymnast on the uneven parallel bars is at rest, tipped at a 45° angle from the vertical. The distance from her hands to her feet is 1.8 m. If we model her body as having a uniform cross section and assume that her center of gravity is midway between her hands and her feet, what is her initial angular acceleration?

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To calculate the initial angular acceleration of the gymnast we can use the principle of torque and ... View full answer
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