Finally, suppose the train in Figure 2.22 slows to a stop from a velocity of 20.0 km/h

Question:

Finally, suppose the train in Figure 2.22 slows to a stop from a velocity of 20.0 km/h in 10.0 s. What is its average acceleration?

Data given in Figure 2.22

0 Ax'= -1.50 km 0. x= 3.75 km x = 5.25 km x (km)

Strategy
Once again, let’s draw a sketch:

Vo -20 km/h V = 0 km/h y X

As before, we must find the change in velocity and the change in time to calculate average acceleration.

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