What is the average velocity of the train in part b of Example 2.2, and shown again
Question:
What is the average velocity of the train in part b of Example 2.2, and shown again below, if it takes 5.00 min to make its trip?
Data given in Example 2.2 part b
Strategy
Average velocity is displacement divided by time. It will be negative here, since the train moves to the left and has a negative displacement.
Transcribed Image Text:
0 Ax'= -1.50 km 0.º x = 3.75 km x = 5.25 km x (km)
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1 Identify the knowns x f 375 km x 0 525 km t 5...View the full answer
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