A physician is making an image with ultrasound of initial intensity (1000 mathrm{~W} / mathrm{m}^{2}). When the

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A physician is making an image with ultrasound of initial intensity \(1000 \mathrm{~W} / \mathrm{m}^{2}\). When the frequency is set to \(1.0 \mathrm{MHz}\), the intensity drops to \(500 \mathrm{~W} / \mathrm{m}^{2}\) at a certain depth in the patient's body. What will be the intensity at this depth if the physician changes the frequency to \(2.0 \mathrm{MHz}\) ?

A. \(750 \mathrm{~W} / \mathrm{m}^{2}\)

B. \(500 \mathrm{~W} / \mathrm{m}^{2}\)

C. \(250 \mathrm{~W} / \mathrm{m}^{2}\)

D. \(125 \mathrm{~W} / \mathrm{m}^{2}\)

Ultrasound is absorbed in the body; this complicates the use of ultrasound to image tissues. The intensity of a beam of ultrasound decreases by a factor of 2 after traveling a distance of 40 wavelengths. Each additional travel of 40 wavelengths results in a decrease by another factor of 2 .

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College Physics A Strategic Approach

ISBN: 9780321907240

3rd Edition

Authors: Randall D. Knight, Brian Jones, Stuart Field

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