A proton with v = 300 m/s is moving through a region in which the magnetic field
Question:
A proton with v = 300 m/s is moving through a region in which the magnetic field is B = 2.5 T. If the magnitude of the force on the proton is 6.4x10-17 N, what angle does the proton’s velocity make with B(vector) the proton is 6.4 ?
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Use the equation for the magnetic force on a moving charge in a magnetic field Solve for the ...View the full answer
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Related Book For 
College Physics Reasoning and Relationships
ISBN: 978-0840058195
2nd edition
Authors: Nicholas Giordano
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