Question: Consider again diffraction from a crystal in Problem 43, but now assume light with = 600 nm is used. What is the diffraction angle

Consider again diffraction from a crystal in Problem 43, but now assume light with λ = 600 nm is used. What is the diffraction angle for the first bright fringe? Your answer explains why visible light cannot be used in diffraction experiments with crystals.

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We can use the same expression derived in Problem 2543 to find the diffraction angle for ... View full answer

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