Question: The transfer function of a phase lead network, as shown in the Fig. M8.14 is (frac{mathrm{K}(1+0.3 s)}{(1+0.17 s)}) The values of (mathrm{R}_{1}) and (mathrm{R}_{2}) are
The transfer function of a phase lead network, as shown in the Fig. M8.14 is \(\frac{\mathrm{K}(1+0.3 s)}{(1+0.17 s)}\)
The values of \(\mathrm{R}_{1}\) and \(\mathrm{R}_{2}\) are respectively:

(a) \(300 \mathrm{k} \Omega\) and \(300 \mathrm{k} \Omega\)
(b) \(300 \mathrm{k} \Omega\) and \(400 \mathrm{k} \Omega\)
(c) \(400 \mathrm{k} \Omega\) and \(300 \mathrm{k} \Omega\)
(d) \(400 \mathrm{k} \Omega\) and \(400 \mathrm{k} \Omega\)
Input O R C = 1 F R Output O
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The given transfer function is of a phase lead network and is given by Hs fracK103 s1017 s The circu... View full answer
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