Question: Show that accuracy is a function of sensitivity and specificity, that is, prove Eq. (6.25). P (P + N) accuracy = sensitivity. N (P+N) +

Show that accuracy is a function of sensitivity and specificity, that is, prove Eq. (6.25).

P (P + N) accuracy = sensitivity. N (P+N) +specificity. (6.25)

P (P + N) accuracy = sensitivity. N (P+N) + specificity. (6.25)

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