Question: Show that if we do all arithmetic modulo a prime number, p, then, for any integer x > 0, {ix mod p: i = 0,
Show that if we do all arithmetic modulo a prime number, p, then, for any integer x > 0,
{ix mod p: i = 0, 1,...,p − 1} = {i : i = 0, 1,...,p − 1}.
Use the fact that if p is prime, then every nonzero integer less than p has a multiplicative inverse when we do arithmetic modulo p.
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Let x be an integer greater than 0 that is modulo p We then have a set of numbers ix mod p ... View full answer
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