Show that if d(n) is O( (n)) and e(n) is O(g(n)), then d(n) +e(n) is O(
Question:
Show that if d(n) is O( ∫ (n)) and e(n) is O(g(n)), then d(n) +e(n) is O( ∫ (n)+g(n)).
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Algorithm Ex1(A): Input: An array A storing n ≥ 1 integers. Output: The sum of the elements in A. S← A[0] for i 1 to n - 1 do s+s+A[i] return s Algorithm Ex2(A): Input: An array A storing n> 1 integers. Output: The sum of the elements at even cells in A. S← A[0] for i 2 to n-1 by increments of 2 do s+s+A[i] return s Algorithm Ex3(A): Input: An array A storing n ≥ 1 integers. Output: The sum of the prefix sums in A. -0 S← for i 0 to n-1 do s+S+A[0] for j1 to i do s+s+A[j]
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Solution We can do this because dn en is defined from 0 through n Also in the special c...View the full answer
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Related Book For
Data Structures And Algorithms In C++
ISBN: 9780470383278
2nd Edition
Authors: Michael T. Goodrich, Roberto Tamassia, David M. Mount
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