Question: Suppose the distribution of y i | is Poisson, We will obtain a sample of observations, y i , . . . , y

Suppose the distribution of yi| λ is Poisson,

exp(-1)2% y!! exp(-1)a ( + 1) f(y; |2) = %3D 0, 1,

We will obtain a sample of observations, yi , . . . , yn. Suppose our prior for λ is the inverted gamma, which will imply

..., > 0.

a. Construct the likelihood function, p(y1, . . . , yn | λ).b. Construct the posterior density

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c. Prove that the Bayesian estimator of λ is the posterior mean, E[λ | y1 , . . . , yn] = y̅.

d. Prove that the posterior variance is Var[λ | yl, . . . , yn] = y̅/n.

exp(-1)2% y!! exp(-1)a ( + 1) f(y; |2) = %3D 0, 1, ..., > 0.

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a The likelihood function is b The posterior is The product of factorials will fall out This ... View full answer

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