Question: 11.3 a. Answer (a) through (c) from Exercise 11.1 using the results in column (3). b. Sketch the predicted probabilities from the probit and linear
11.3
a. Answer
(a) through
(c) from Exercise 11.1 using the results in column (3).
b. Sketch the predicted probabilities from the probit and linear probability in columns (1) and (3) as a function of Schoolingi for values of Schooling between 0 and 18. Do you think that the linear probability is appropriate here? Why or why not? 
Dependent Variable: Gov Linear Linear Probit Logit Probability Probit Logit Probability Probit (1) (2) (3) (4) (5) (6) (7) Schooling 0.272 0.551 0.035 0.548 (0.029) (0.062) (0.003) (0.091) Male -0.242 -0.455 -0.050 (0.125) (0.234) (0.025) 4.352 (1.291) Male X Schooling Constant -.344 (0.096) -4.107 -8.146 -0.172 -1.027 -1.717 0.152 -7.702 (0.358) (0.800) (0.027) (0.098) (0.179) (0.021) (1.238)
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