The circle with equation (x 4) 2 + (y + 7) 2 = 50 meets the
Question:
The circle with equation (x − 4)2 + (y + 7)2 = 50 meets the straight line with equation x − y − 5 = 0 at points A and B.
a. Find the coordinates of the points A and B.
b. Find the equation of the perpendicular bisector of line segment AB.
c. Show that the perpendicular bisector of AB passes through the centre of the circle.
d. Find the area of triangle OAB.
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Step by Step Answer:
To solve the given problem lets go step by step a Find the coordinates of points A and B We have two equations The equation of the circle x 42 y 72 50 ...View the full answer
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Related Book For 
Edexcel AS And A Level Mathematics Pure Mathematics Year 1/AS
ISBN: 9781292183398
1st Edition
Authors: Greg Attwood
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