Question: Prove (11.32) . E (Yi,k | Zi = 0, = e) = E (Yi,k | i = 1, = e) = E (Yi,k

Prove (11.32)       .

    E (Yi,k | Zi = 0, = e) = E (Yi,k |

E (Yi,k | Zi = 0, = e) = E (Yi,k | i = 1, = e) = E (Yi,k | Ti = e), k = 1,2. (11.32)

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