Question: In Example 9.17, the alternate hypothesis was H1: 3.5 and the P-value for the two-tailed test was P = 0.0256. What would the

In Example 9.17, the alternate hypothesis was H1: μ ≠ 3.5 and the P-value for the two-tailed test was P = 0.0256. What would the P-value be for the alternate hypothesis H1: μ

Example 9.17 Perform a hypothesis test Generic drugs are lower-cost substitutes for

Example 9.17 Perform a hypothesis test Generic drugs are lower-cost substitutes for brand-name drugs. Before a generic drug can be sold in the United States, it must be tested and found to perform equivalently to the brand- name product. The U.S. Food and Drug Administration is now supervising the testing of a new generic antifungal ointment. The brand-name ointment is known to deliver a mean of 3.5 micrograms of active ingredient to each square centimeter of skin. As part of the testing, seven subjects apply the ointment. Six hours later, the amount of drug that has been absorbed into the skin is measured. The amounts, in micrograms, are 2.6 3.2 2.1 3.0 3.1 2.9 3.7 How strong is the evidence that the mean amount absorbed differs from 3.5 micrograms? Use the a=0.01 level of significance.

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