An empirical equation for the velocity distribution in a horizontal, rectangular, open channel is given by u u max (y d) n , where u is the velocity at a distance y meters above the floor of the channel If the depth d of flow is 1 7 m, u max 9 m s, and n 1 6, what is the discharge in cubic meters p...

An empirical equation for the velocity distribution in a horizontal, rectangular, open channel is given by u

Question:

An empirical equation for the velocity distribution in a horizontal, rectangular, open channel is given by u = u_max (y/d)ⁿ, where u is the velocity at a distance y meters above the floor of the channel. If the depth d of flow is 1.7 m, u_max = 9 m/s, and n = 1/6, what is the discharge in cubic meters per second per meter of width of channel? What is the mean velocity?

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