A tape having a thickness s wraps around the wheel which is turning at a constant rate
Question:
A tape having a thickness s wraps around the wheel which is turning at a constant rate ω. Assuming the unwrapped portion of tape remains horizontal, determine the acceleration of point P of the unwrapped tape when the radius of the wrapped tape is r. Since vP = ωr, take the time derivative and note that dr/dt = ω (s/2π).
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: