The acceleration of a particle is given by a = kt 2 , where a is in
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The acceleration of a particle is given by a = −kt2, where a is in meters per second squared and the time t is in seconds. If the initial velocity of the particle at t = 0 is v0 = 12 m/s and the particle takes 6 seconds to reverse direction, determine the magnitude and units of the constant k. What is the net displacement of the particle over the same 6-second interval of motion?
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-+ s, ft or m -1 1 2 3
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The magnitude of the constant k can be determined by using the equ...View the full answer
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Related Book For
Engineering Mechanics Dynamics
ISBN: 9781118885840
8th Edition
Authors: James L. Meriam, L. G. Kraige, J. N. Bolton
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