The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t)
Question:
The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t) N, where t is in seconds. Write the equation which describes the steady-state motion.
Transcribed Image Text:
k = 400 N/m 50000 W k = 400 N/m 20 kg F = 90 cos 6t D c=125 N s/m
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Related Book For
Engineering Mechanics Statics & Dynamics
ISBN: 9780134895154
15th Edition
Authors: Russell C. Hibbeler
Question Posted:
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