Draw a diagram like Fig. 31.10, but showing a ray from the arrowhead through the center of curvature. Using the fact that this ray reflects back on itself, draw similar triangles with object and image as their vertical sides, and show that the center of curvature is twice as far from the mirror as the focal point?that is, R = 2f, with R the curvature radius.

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C (a) Similar triangles, so h'/h = -s'/s Similar triangles, so –h'/h = (s' – f)/f C. -h' (b)