Where in Fig 20 5 could you put a third charge so it would experience no net force Would it be in stable or unstable equilibrium 9 1 0C 92 1 5MC x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of The unit vector is in the direction from q, to q2 so here it's

Question: Where in Fig. 20.5 could you put a third charge so it would experience no net force? Would it be in stable or unstable equilibrium?

Where in Fig. 20.5 could you put a third charge so it would experience no net force? Would it be in stable or unstable equilibrium?

9. = 1.0µC 92 =-1.5MC -x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of ?

9. = 1.0C 92 =-1.5MC -x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of . The unit vector is in the direction from q, to q2. so here it's .

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