Where in Fig 20 5 could you put a third charge so it would experience no net force Would it be in stable or unstable equilibrium 9 1 0C 92 1 5MC x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of The unit vector is in the direction from q, to q2 so here i...

You would have to put the third charge somewhere to the ...

Where in Fig. 20.5 could you put a third charge so it would experience no net force?

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Where in Fig. 20.5 could you put a third charge so it would experience no net force? Would it be in stable or unstable equilibrium?

9. = 1.0µC 92 =-1.5MC -x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of ?

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Question Posted: Jan 14, 2019 01:24 PM

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Where in Fig. 20.5 could you put a third charge so it would experience no net force?

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9. = 1.0µC 92 =-1.5MC -x(cm) The charges have opposite signs, so q192 is negative, and F is opposite the direction of î. The unit vector is in the direction from q, to q2. so here it's î.

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