Question: Exercises 2.5 It^o's isometry Let us consider a deterministic function f : R ! R. 1. Prove that EP[ Z t 0 f(s)dWs] = 0
Exercises 2.5 It^o's isometry Let us consider a deterministic function f : R ! R.
1. Prove that EP[
Z t 0
f(s)dWs] = 0 EP[
Z t 0
f(s)dWs
2
] =
Z t 0
f(s)2ds Hint: Assume that f(s) can be approximated by simple functions (s) =
i1si
These expressions can be extended to the case where f(s; !) is an adapted process. We have the It^o isometry formula:
EP[
Z t 0
f(s; !)dWs] = 0 EP[
Z t 0
f(s; !)dWs
2
] =
Z t 0
EP[f(s; !)2]ds 2. Let Z 2 N(0; 2) be a normal r.v. with zero mean and variance equal to 2. Prove that E[eZ] = e
2 2
3. Deduce that EP[e R t 0 f(s)dWs ] = e 1
2 R t 0 f(s)2ds
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
