Question: (a) It is well known that the model in which air resistance is ignored, part (a)of Problem 36, predicts that the time t a it
(a) It is well known that the model in which air resistance is ignored, part (a)of Problem 36, predicts that the time tait takes the cannonball to attain its maximum height is the same as the time tdit takes the cannonball to fall from the maximum height to the ground. Moreover, the magnitude of the impact velocity viwill be the same as the initial velocity v0of the cannonball. Verify both of these results.
(b) Then, using the model in Problem 37 that takes air resistance into account, compare the value of ta with td and thevalue of the magnitude of vi with v0. A root-finding application of a CAS (or graphic calculator) may be useful here.
Data from problem 36
Suppose a small cannonball weighing 16 pounds is shot vertically upward, as shown in the following figure, with an initial velocity v0 = 300 ft/s. The answer to the question How high does the cannonball go? depends on whether we take air resistance into account.
Suppose air resistance is ignored. If the positive direction is upward, then a model for the state of the cannonball is given by d2s/dt2 = -g (equation (12) of Section 1.3). Since ds/dt = v(t) the last differential equation is the same as dv/dt = -g, where we take g = 32 ft/s2. Find the velocity v(t) of the cannonball at time t.

mg ground level
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a We saw in part a of Problem 36 that the ascent time is t a 93... View full answer
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