Question: Find an explicit solution of the given initial-value problem. 1. dx/dt = 4(x 2 + 2), x(/4) =1 2. dy/dx = (y 2 - 2)/

Fi­nd an explicit solution of the given initial-value problem.

1. dx/dt = 4(x2 + 2), x(π/4) =1

2. dy/dx = (y2 - 2)/ (x2 - 1), y(2) = 2

3. x2 dy/dx = y – xy, y(-1) = -1

4. dy/dt + 2y = 1, y(0) = 5/2

5. √(1 – y2) dx – √(1 – x2) dy = 0, y(0) = √3 / 2

6. √(1 – y4) dy + x(1 + 4y2) dx = 0, y(1) = 0

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1 From 1x 2 1 dx 4 dt we obtain tan 1 x 4tc Using x4 1 we find c 34 The solution of the initialvalue ... View full answer

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