Question: In Problem solve the given differential equation (2r 2 cos sin + r cos ) d + (4r + sin - 2r

In Problem solve the given differential equation

(2r2 cos θ sin θ + r cos θ) dθ + (4r + sin θ - 2r cos 2 θ) dr = 0 

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Letting M 2r 2 cos sin r cos And N 4r sin 2r cos 2 we see that M ... View full answer

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