A crystal is growing from a supersaturated solution at a rate of (0.2 mu mathrm{m} / mathrm{s}).
Question:
A crystal is growing from a supersaturated solution at a rate of \(0.2 \mu \mathrm{m} / \mathrm{s}\). The solution contains 4 moles/lit of solute and saturated conditions have been measured to be 3.95 moles/ lit at the conditions of the test. The crystal is \(1 \mathrm{~mm}\) in diameter and the fluid flows past the crystal at a velocity of \(0.5 \mathrm{~m} / \mathrm{s}\). The viscosity of the fluid is \(5 \times 10^{-3} \mathrm{Ns} / \mathrm{m}^{2}\) and its density is \(1100 \mathrm{~kg} / \mathrm{m}^{3}\). The solid has a density of \(1500 \mathrm{~kg} / \mathrm{m}^{3}\) and its molecular weight is 150 . The diffusion coefficient for the solute in the liquid is \(4 \times 10^{-10} \mathrm{~m}^{2} / \mathrm{s}\). How fast could the crystal grow in this solution? Is there some resistance to forming the actual crystal, and if so, what is its magnitude?
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