The equation below gives the boiling temperature of isopropanol as a function of pressure: T = B

The equation below gives the boiling temperature of isopropanol as a function of pressure:

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T = B A - log10 P - C, where T' is in kelvin, P is in bar, and the parameters A, B, and Care A = 4.57795, B = 1221.423, C = -87.474 Obtain an equation that gives the boiling temperature in °F, as a function of In P, with P in psi. Hint: The equation is of the form T= B' A' - In P but the constants A', B', and C' have different values from those given above.