An oxygen molecule with mass m = M m o = 32 1.66 10 27
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An oxygen molecule with mass m = M mo = 32 × 1.66 × 10−27 kg moves with a velocity of 240 m/s. What is the kinetic energy of the molecule? What temperature does that corresponds to if it has to equal (3/2) kT, where k is Boltzmans constant and T is absolute temperature in Kelvin?
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Kinetic energy mv2 1232 166 1027 kg240 ms2 840 1021 J T...View the full answer
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Related Book For 
Fundamentals Of Thermodynamics
ISBN: 9781118131992
8th Edition
Authors: Claus Borgnakke, Richard E. Sonntag
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