A 2.05 g sample of an ironaluminum alloy (ferroaluminum) is dissolved in excess HCl(aq) to produce 0.105
Question:
A 2.05 g sample of an iron–aluminum alloy (ferroaluminum) is dissolved in excess HCl(aq) to produce 0.105 g H2(g). What is the percent composition, by mass, of the ferroaluminum?
Fe(s) + 2 HCl(aq) → FeCl2(aq) + H2(g)
2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g).
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To find the percent composition by mass of the ferroaluminum in the alloy we need to calculate the m...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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