For the half-cell reaction Hg 2+ (aq) + 2 e - Hg(l), E = 0.854 V.
Question:
For the half-cell reaction Hg2+(aq) + 2 e- → Hg(l), E° = 0.854 V. This means that
(a) Hg(l) is more readily oxidized than H2(g);
(b) Hg2+(aq) is more readily reduced than H+(aq);
(c) Hg(l) will dissolve in 1M HCl;
(d) Hg(l) will displace Zn(s) from an aqueous solution of Zn2+ ion.
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The standard reduction potential E for the halfcell reaction Hgaq 2e Hgl is 0854 V This value tells ...View the full answer
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Related Book For
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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