The value of E cell for the reaction Zn(s) + Pb 2+ (aq) Zn 2+ (aq)
Question:
The value of E°cell for the reaction Zn(s) + Pb2+(aq) → Zn2+(aq) + Pb(s) is 0.66 V. This means that for the reaction Zn(s) + Pb2+(0.01 M) → Zn2+(0.10 M) + Pb(s), Ecell equals
(a) 0.72 V;
(b) 0.69 V;
(c) 0.66 V;
(d) 0.63 V.
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The Nernst equation can be used to calculate the cell potential of a reaction unde...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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