Question: Given the following standard potentials in basic solution and assuming that a reversible reaction can be established on a suitable catalyst, calculate E ,

Given the following standard potentials in basic solution

CrO2 (aq) + 4HO(l) + 3e Cr(OH), (s) + 5OH- (aq) E

and assuming that a reversible reaction can be established on a suitable catalyst, calculate E, ΔrG, and K for the reductions of

(a) CrO42− 

(b) [Cu(NH3)2]+ in basic solution. Comment on why ΔrG and K are so different between the two cases despite the values of E being so similar.

CrO2 (aq) + 4HO(l) + 3e Cr(OH), (s) + 5OH- (aq) E = -0.11 V [Cu(NH)](aq) + eCu(s) + 2NH (aq) E* = -0.10 V

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