Question: [Ir(CN) 6 ] 3 has a regular octahedral structure. For K 3 [Ir(CN) 6 ], the wavenumbers corresponding to the CN stretching modes are 2167
[Ir(CN)6]3− has a regular octahedral structure. For K3[Ir(CN)6], the wavenumbers corresponding to the C≡N stretching modes are 2167 (A1g), 2143 (Eg) and 2130 (T1u) cm–1.
(a) To which point group does [Ir(CN)6]3− belong?
(b) What would you observe in the IR spectrum of K3[Ir(CN)6] in the region between 2200 and 2000 cm–1?
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a To determine the point group of IrCN63 we need to analyze the symmetry of the molecule and its vib... View full answer
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