The reaction of Cr(CO) 6 with Ph 2 P(CH 2 ) 4 PPh 2 leads to the formation of two products, A and B The 31 P NMR spectrum of A shows two signals ( 46 0 and 16 9 ppm, relative integrals 1 1), while that of B exhibits one signal ( 46 2 ppm) The IR spectra of A and B are almost identical in the region...

Based on the provided information it appears that the reaction of CrCO6 with Ph2PCH24PPh2 produces two products A and B The 31P NMR spectrum of A show ...

The reaction of Cr(CO) 6 with Ph 2 P(CH 2 ) 4 PPh 2 leads to the

Question:

The reaction of Cr(CO)₆ with Ph₂P(CH₂)₄PPh₂ leads to the formation of two products, A and B. The ³¹P NMR spectrum of A shows two signals (δ + 46.0 and –16.9 ppm, relative integrals 1 : 1), while that of B exhibits one signal (δ + 46.2 ppm). The IR spectra of A and B are almost identical in the region 2200–1900 cm^–1, with bands at 2063, 1983 and 1937 cm^–1. Suggest identities for A and B and explain why three absorptions are observed in the IR spectrum of each compound.